Craig is standing on his apartment balcony and locates his car in the street-level parking lot below. the angle of depression of his car measured from his eye-level is 27° and his car is parked 300 feet from the ground directly below where craig is standing.
how high is the base of craig's balcony from the ground to the nearest foot, if craig's eye-level is 6 feet from the base of the balcony?
a. 583 feet
b. 147 feet
c. 261 feet
d. 130 feet

I've been working on this for a few days and i just don't understand, it's due in a few hours. you. the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α. part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part b suppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i. e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case. part c now try a numerical problem. what is the direction of the vector w = < -1, 6 > ?