(08.01) the graph shows two lines, q and s. a coordinate plane is shown with two lines graphed. line q has a slope of one half and crosses the y axis at 3. line s has a slope of one half and crosses the y axis at negative 2. how many solutions are there for the pair of equations for lines q and s? explain your answer.

There are no solutions for the pair of equations.

The lines are parallel to each other

Step-by-step explanation:

Line Q has a slope of 1/2 and crosses the y axis at 3.

This mean at x=0, y=3

Using the equation of a straight line expression to find the slope

y=mx +c  where m is slope and c in the y intercept you can write the equation for Line Q as;

For the Line S , slope is 1/2  and the line crosses the y axis at -2 , which represents the c in the equation y=mx +c

The equation for S will be

Using the graphing tool to plot the two equations for line  Q and line S we notice that the lines are parallel .For solutions, they have to intersect.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

2

step-by-step explanation: