Afrog (with webbed feet for sticking to a vertical surface) falls into a 6 ft deep hole with vertical sides. as the frog tries to escape, it is able to jump up 3 ft on a jump, but then slides back down 2 ft before it can jump again. if this continues, how many jumps will it take the frog to reach the top of the hole?

4

Step-by-step explanation:

Assuming that the frog is consistent with its performance, the correct answer can be calculated. It can be noticed that the ability to jump upwards is 3 feet and the sliding back down is 2 feet. This means that the gain is greater than the loss. The net gain is 1 foot for each jump. This will continue until the distance of 6 feet has been achieved. It will be: 3 ft - 2 ft = 1 ft (1 jump); 1 ft + 3 ft - 2 ft = 2 ft (2 jumps); 2 ft + 3 ft - 2 ft = 3 ft (3 jumps). At the end of the 3 jumps, the frog has already covered the distance of 3 feet. This means that when the frog jumps from this height, it will achieve the height of 6 feet, by which it will get out of the hole. This means that the frog requires 4 jumps to get out of the tunnel.

17

step-by-step explanation:

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.