In 2012 the population at a middle school was 695 students. in 2016, the population had grown to 825 students. assuming a constant rate of change, predict the population of the school in 2018.
890 students
725 students
850 students
760 students

These kind of problem can be modeled by using the following equation

y = Po*e^(k*(t-to))

Where

Po = initial population

to = year of the initial population

y = Number of students at current year

k = constant rate of change

t = time in years

In 2012

695 = Po*e^(k*(2012 - 2012))

Po = 695

In 2016

825 = 695.e^(k*(2016-2012))

825/695 = e^(k*(4))

ln(825/695) = 4*k

k = ln(825/695) / 4

k = ln(825/695) / 4

k = 0.04287

in 2018

y = 695*e^(0.04287*(2018-2012))

y = 695*e^(0.04287*(6))

y = 695*e^(0.257)

y = 695*1.293

y = 898.85

approximately

899 students

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .