How many solutions exist for given equation 12x + 1 = 3(4x + 1

no solutions

Step-by-step explanation:

12x + 1 = 3(4x + 1)

Distribute the 3

12x + 1 = 12x + 3

Subtract 12x from each side

12x-12x +1 = 12x-12x+3

1 =3

This is never true, so there are no solutions

There are no solution

Step-by-step explanation:

A(B+C)=ab+ac

3(4x+1)=12x+1

12x+1=12x+3

Subtract by 1 both sides of equation.

12x+1-1=12x+3-1

Simplify.

3-1=2

12x=12x+2

Then subtract by 12x both sides of equation.

12x-12=12x+2-12x

Simplify, to find the answer.

0=2

The sides are not equal.

It's should be no solution.

No solution is the correct answer.

i can't read the graph

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.