For a standard normal distribution (µ=0, σ=1), the area under the curve less than 1.25 is 0.894. what is the approximate percentage of the area under the curve less than -1.25?

The approximate percentage of the area under the curve less than -1.25 is 10.6%

For a Symmetric distribution :

The total area under the curve = 1

Hence,

P(Z < x) + P(Z > x) = 1

If the area under the curve less than 1.25 = 0.894

P(Z < 1.25) = 0.894

The percentage are under the curve less Than - 1.25 can be expressed as :

P(Z < - 1.25) = 1 - P(Z < 1.25) = 1 - 0.894

P(Z < - 1.25) = 0.106

Hence,

P(Z < - 1.25) = 10.6%

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10.6%

Step-by-step explanation:

Normal curves are symmetrical.  That means that on a standard normal distribution,  the area less than -1.25 is the same as the area greater than +1.25.  The total area under the curve is 1, so:

P = 1 - 0.894

P = 0.106

Approximately 10.6% of the area under the curve lies below -1.25.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18