The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [hint: use a/r , a, and ar to represent the first three terms, respectively.] the three numbers are and

-1/10, -1/5 , -2/5 or -2/5, -1/5 , -1/10

Step-by-step explanation:

let a/r, a, ar  be the first 3 terms of the geometric series

their product would be equal to a^3

a^3=-1/125

a=-1/5

Substitute a=-1/5 into the first 3 terms

-1/5r + -1/5+-r/5=-7/10

Multiply the terms such that they have a common denominator:

-1/5r +-r/5r + -r^2/5r = -3.5r/5r

Multiply both sides by 5r

-r^2-r-1=-3.5r

Add 3.5r to both sides and multiply the equation by 2

-2r^2 + 5r -2=0

Factorize the equation

(2r-1)(r-2)=0

r=0.5 or r-2

For the first three terms where r=0.5

-2/5, -1/5 , -1/10

For the first three terms where r=2

-1/10, -1/5 , -2/5

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: