The number of pieces of popcorn in a large movie theater popcorn bucket is normally distributed, with a mean of 1610 and a standard deviation of 10. approximately what percentage of buckets contain between 1600 and 1620 pieces of popcorn?

a. approximately 68%
b. approximately 75%
c. approximately 95%
d. approximately 99.7%

A. Approximately 68%

Step-by-step explanation:

Number of pieces of popcorn in a bucket is normally distributed.

Mean = μ = 1610

Standard deviation = б = 10

We know that in normal distribution, approximately 34% of bags will fall with in one standard deviation on one side. On both sides within the range of 1 standard deviation, 34 + 34 = 68 % of bags will fall.

A table of normal distribution about mean is attached for better understanding.

Our range is:

1600 to 1620

1610 - 10 to 1610 + 10

μ ± б

mean ± 1 standard deviation

Our range is within 1 standard deviation. Hence, Approximately 68% of buckets contain between 1600 and 1620 pieces of popcorn.

im a goose

step-by-step explanation:

gg5

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm