One number is 4 less than 3 times a second number. if 3 more than two times the first number is decreased by 2 times the second number, the result is 11. use the substitution method. what is the first number?

The first number is 8

Step-by-step explanation:

Let

x > the first number

y > the second number

x=3y-4 > equation A

3+2x-2y=11 > equation B

Substitute equation A in equation B and solve for y

3+2(3y-4)-2y=11

3+6y-8-2y=11

4y=11+5

y=16/4=4

Find the value of x

x=3(4)-4=8

a² + b²= c²

24² + 7² = c²

c= 25

i can you with this sweetie!

step-by-step explanation: