Any is very appreciated! (picture is provided below)not sure how to do this at all won't lie

(-2,0.2)

Step-by-step explanation:  

we have

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The intersection points are (-1.9,0.2) and (1,6)

see the attached figure

therefore

The solution of the system of equations are the points (-1.9,0.2) and (1,6)

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)