For which pairs of functions is (f•g)(x)=12x? f(x)=3-4x and g(x)=16x-3 f(x)=6x2 and g(x)= 2/x f(x)= and g(x) = 144x f(x)=4x and g(x) =3x

F(x)=4x and g(x) =3x

Step-by-step explanation:

We will have to check each pair of functions one by one

So,

For f(x)=3-4x and g(x)=16x-3

For composition we have to put g(x) in place of x in f(x)

(fog)(x)=3-4(g(x))

= 3-4(16x-3)

=3-64x+12

=-64x+15

So first pair doesn't give 12x.

Now for,

F(x)=6x2 and g(x)= 2/x

(fog)(x)= 6(g(x))^2

=6(2/x)^2

=6*(4/x^2)

=24/x^2

For the last pair:

F(x)=4x and g(x) =3x

(fog)(x)=4(g(x))

=4(3x)=12x

So for the last pair of functions (fog)(x) is 12x ..

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

answer: do we write it

step-by-step explanation: