Astudent draws two parabolas on graph paper. both parabolas cross the x-axis at (–4, 0) and (6, 0). the y-intercept of the first parabola is (0, –12). the y-intercept of the second parabola is (0, –24). what is the positive difference between the a values for the two functions that describe the parabolas? write your answer as a decimal rounded to the nearest tenth

Lets say that y1 is the parabola with y intercept of (0,-12)

y1 = A(x+4)(x+6)

-12 = A(+4)(+6)

A = -0.5

y1 = -0.5(x+4)(x+6)

Step-by-step explanation:

The parabolas can be described

y = A.(x-x1)(x-x2)

where x1 and x2 are the crossing points in the x-axis

x1 = -4

x2 = 6

Lets say that y1 is the parabola with y intercept of (0,-12)

y1 = A(x+4)(x+6)

-12 = A(+4)(+6)

A = -0.5

y1 = -0.5(x+4)(x+6)

Lets say that y2 is the parabola with y intercept of (0,-24)

y2 = B(x+4)(x+6)

-24 = B(+4)(+6)

B = -1

y2 = -(x+4)(x+6)

The positive difference is 0.5

-0.5

Step-by-step explanation:

a. 74 degrees

step-by-step explanation:

because the lines through the side and the box in the corners shows that these are congruent triangles and since they are mirrored the 37 degrees is also mirrored so the answer is 37 * 2 which is 74.

practice. practice. practice.