Given sin28.4=.4756, cos28.4=.8796, and tan28.4=.5407 find the cot of 61.6

The cotangent of 61.6° is .5407.

Step-by-step explanation:

Refer to the sketch attached.

61.6° + 28.4° = 90°. In other words, 61.6° is the complementary angle of 28.4°.

Consider a right triangle OAB with a 61.6° angle . The other acute angle will be 28.4°.

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The cotangent of an angle is the reciprocal of its tangent.

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In other words,

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21

jk it's 20

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true