Sales personnel for skillings distributors submit weekly reports listing the customer contacts made during the week. a sample of 55 weekly reports showed a sample mean of 17.5 customer contacts per week. the sample standard deviation was 5.8. provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel. a. 90% confidence interval, to 2 decimals b. 95% confidence interval, to 2 decimals

15

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

c

step-by-step explanation:

i think because what else can be a sample of every member