Which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 + 2x – 1 into the quadratic formula below? quadratic formula: x =

a = 4, b = 2 and c= -1

Step-by-step explanation:

Quadratic formula: x =√[-b ± v(b² - 4ac)]/2a

Here quadratic equation is  4x2 + 2x – 1

a = 4, b = 2 and c= -1

x =[-b ± √(b² - 4ac)]/2a

 = [-2 ± √(2² - 4*4*-1)]/2*4

 = [-2 ± √(4  + 16)]/8

 = [-2 ± √20)]/8

 = [-2 ± 2√5)]/8

 =  [-1 ± √5)]/4

x = [-1 ± √5)]/4

For this case we have a quadratic equation given by:

The roots are found by means of the quadratic formula below:

Where:

So, we have:

Or in an equivalent way we have:

The correct option will be:

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

i would be happy to . most people on would also love to i'm sure. if you just want someone who has done algebra before and want a little more personal relationship than just begging strangers for , i can certainly be of service. i do have college myself so i might not be 24/7.