Six customers enter a three-floor restaurant. each customer decides on which floor to have dinner. assume that the decisions of different customers are independent, and that for each customer, each floor is equally likely. find the probability that exactly one customer dines on the first floor.

The probability that exactly one customer dines on the first floor is:

                     0.26337  

We need to use the binomial theorem to find the probability.

The probability of k success in n experiments is given by:

where p is the probability of success.

Here p=1/3

( It represents the probability of choosing first floor)

k=1 ( since only one customer has to chose first floor)

n=6 since there are a total of 6 customers.

This means that:

it is true

step-by-step explanation:

all the combinations add up i used   calculator

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .