What is the slope of the line defined by the parametric equations x=-2+4t and y=1+4t ?

The value of slope m = -1

Step-by-step explanation:

x = -2 + 4t

and y = 1 + 4t

Solving the both equations

x +2 = 4t

=> t = (x+2)/4     eq(1)

y-1 = 4t

=> t = (y-1)/4      eq(2)

Putting eq(1) = eq(2) as left hand side of both equations are same

(x+2)/4 = (y-1)/4

Cross multiplying

4(x+2) = 4(y-1)

4x + 8 = 4y -4

4x +4y = -4 -8

4x + 4y = -12

4(x+y) = -12

x+y = -12/4

x+y = -3

y = -x -3

The slope intercept form of line is:

y = mx + b

where m is the slope. Comparing with y = -x-3

The value of slope m = -1

here is the

mark brainliest pl

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube