[tex]rac{a}{x-8} +rac{b}{x+4} =rac{2x-64}{(x-8)(x+4)}[/tex]solv e for a and b

a = -4b = 6Step-by-step explanation:See attached...

Mathematics, 22.06.2019 21:10 maued

$\frac{a}{x-8} +\frac{b}{x+4} =\frac{2x-64}{(x-8)(x+4)}$ solv e for a and b

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[tex]\frac{a}{x-8} +\frac{b}{x+4} =\frac{2x-64}{(x-8)(x+4)}[/tex]solv e for a and b...