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Mathematics, 22.06.2019 21:10 maued

\frac{a}{x-8} +\frac{b}{x+4} =\frac{2x-64}{(x-8)(x+4)}solv e for a and b

Answers

ansver
Answer from: sharondot2398

a = -4

b = 6

Step-by-step explanation:

See attached


<img src=solve for a and b" />
ansver
Answer from: littlecedrick7368

a=-4 and b=6

Step-by-step explanation:

\frac{a}{x-8} +\frac{b}{x+4} =\frac{2x-64}{(x-8)(x+4)}

First, add the fractions by finding the common denominator.

In this case, (x-8)(x+4).

\frac{a(x+4) + b(x-8)}{(x-8)(x+4)} =\frac{2x-64}{(x-8)(x+4)}

Therefore, the numerators are equal:

a(x+4) + b(x-8) =2x-64

Simplify:

ax+4a + bx-8b =2x-64\\(a+b)x+4a-8b=2x-64

Now match the coefficients.

a+b=2, 4a-8b=-64

Solve the system of equations.  I'll use substitution, but you can also use elimination if you prefer.

4a-8b=-64\\a-2b=-16\\(2-b)-2b=-16\\2-3b=-16\\-3b=-18\\b=6\\a=-4

Therefore, a=-4 and b=6.

ansver
Answer from: Quest

fourth month

step-by-step explanation:

it is the one with the most keychains.

ansver
Answer from: Quest
Ithink the answer is c

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[tex]\frac{a}{x-8} +\frac{b}{x+4} =\frac{2x-64}{(x-8)(x+4)}[/tex]solv e for a and b...

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