, 22.06.2019 21:00 aaroneduke558

# Will mark the branliest. beverly has \$50 to spend at an amusement park. admission to the park is \$15. she plans to spend \$10 on food. each ride costs \$1.50. what is the maximum number of rides she can ride? 1. define a variable for this situation. 2. write an inequality to represent the possible number of rides she can ride. 3.solve the inequality from #2 to determine the maximum number of rides she can ride. 4.5. if beverly rides the maximum number of rides possible, will she have spent the entire \$50? if she has not spent the entire \$50, how much money is left over? support your answer with an explanation and/or calculations.

see below

Step-by-step explanation:

Let r = number of rides

total amount of money spent has to be less than  or equal to 50

costs are admission and food and rides

rides cost 1.50 each

50≥ admission + food + rides

50 ≥ 15 +10 + 1.50r

Combine like terms

50 ≥25 + 1.50 r

Subtract 25 from each side

50-25 ≥25-25 + 1.50 r

25  ≥ 1.50 r

Divide by 1.5 on each side

25/1.5 ≥ 1.5r/1.5

50/3  ≥ r

Changing this to a mixed number

16 2/3  ≥r

We can only take a whole number of rides

r = 16

Beverly has not spent all of her 50 dollars since there was a fraction for the rides

cost =  15 +10 + 1.50r

15+10 + 1.5*16

25+24

49

She has 1 dollar left

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!

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