 , 22.06.2019 21:00 hannahbannana98

# Factor completely. -2k - k 3 - 3k 2 a.) k(-k + 1)(k - 2) b.) -k(k - 1)(k - 2) c.) -k(k + 1)(k + 2) -k (k+1) (k+2)

Step-by-step explanation:

-2k - k³ - 3k² (factor-k out)

-k (2 + k² + 3k) (rearrange to standard quadratic form)

-k (k² + 3k + 2) (factor expression inside parentheses using your favorite method)

-k (k+1) (k+2) Option c.

Step-by-step explanation:

The given expression is We need to find the factor form of the given expression.

Taking out HCF. Arrange the terms according to there degree. Splitting the middle terms we get    The factor form of given expression is -k(k+1)(k+2). Therefore, the correct option is c. -2k - k 3 - 3k 2
= - k 3 - 3k 2 -2k
=-k(k^2 +3k + 2)
=-k(k+1)(k+2) -k (k + 2) (k + 2)

Step-by-step explanation: look at the pictures

Step-by-step explanation:     The answer is -k (k + 2) (k+1)

Hope that helps

Step-by-step explanation: -k (k + 2) (k + 1)

Step-by-step explanation:

Factor the following:

-k^3 - 3 k^2 - 2 k

Factor -k out of -k^3 - 3 k^2 - 2 k:

-k (k^2 + 3 k + 2)

The factors of 2 that sum to 3 are 2 and 1. So, k^2 + 3 k + 2 = (k + 2) (k + 1):

-k (k + 2) (k + 1) -k(k + 2)(k + 1)

Step-by-step explanation:

-k is a common factor here.  Factoring -k out, we get:

-k(2 + k^2 + 3k), or (after writing the quadratic in standard form)

-k(k^2 + 3k + 2) = -k(k + 2)(k + 1) Multiply to see that this is true. A second check is also necessary for factoring - we must be sure that the expression has been completely factored. In other words, "Did we remove all common factors? Can we factor ...

Step-by-step explanation:

Multiply to see that this is true. A second check is also necessary for factoring - we must be sure that the expression has been completely factored. In other words, "Did we remove all common factors? Can we factor ... Factor the expression ~
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Factor completely. -2k - k 3 - 3k 2 a.) k(-k + 1)(k - 2) b.) -k(k - 1)(k - 2) c.) -k(k + 1)(k + 2)...

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