, 22.06.2019 21:20 chycooper101

Sue travels by bus or walks when she visits the shops. the probability that she catches the bus to the shops is 0.4. the probability she catches the bus from the shops is 0.7. show the probability that sue walks at one way is 0.72

Proved,

P(A∪B)=0.72

Step-by-step explanation:

Sue travels by bus or walks when she visits the shops.

Probability( catch the bus to the shop ), P(A) = 0.4

Probability( catch the bus from the shop ), P(B) = 0.7

Both A and B are independent events.

Therefore,

P(A∩B) = 0.4×0.7

= 0.28

Probability Sue walks one way = 1 - P(A∩B)

= 1 - 0.28

= 0.72

Hence, the probability that Sue walks at one way is 0.72

0.72

Step-by-step explanation:

0.7x0.4=0.28

1-0.28= 0.72

That is what I did in the box and got the correct answer. Hope you have a good day!

last time i did this i got 1.4

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