Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
a. 1+-/21 i
b.-1+-/19i
c. 1+-2/19i
d. 1+-/19i

To solve x^2 + 20 = 2x. First, we take all values to the left hand side and equate it to zero. x^2 - 2x + 20 = 0 The quadratic formular is given by x = (-b + or - sqrt(b^2 - 4ac)) / 2a, where: a = 1, b = -2 and c = 20 x = (-(-2) + or - sqrt((-2)^2 - (4 x 1 x 20))) / (2 x 1) = (2 + or - sqrt(4 - 80)) = (2 + or - sqrt(-76)) / 2 = (2 + or - 2sqrt(-19)) / 2 = 1 + or - sqrt(-19) = 1 + or - sqrt(19) i. Therefore, the solution to x^2 + 20 = 2x is x = 1 + or - sqrt(19) i (option d).