The pulse rate (in bpm) of a random sample of 30 peruvian indians was collected. the mean pulse rate of the sample was 70.2 and the standard deviation was 10.51. compute the 95% confidence interval for the population mean.

= 70.2 ± 3.761  bpm

Step-by-step explanation:

The question is on calculating the confidence interval for a population mean

The general expression is

CI = x ± z * δ/√n   where;

CI = confidence interval,

 x = mean of sample,

 δ = standard deviation,

  n= is sample size

   z = z* value from standard normal distribution according to   confidence level given.

Given that;

n= 30   x =70.2    δ=10.51          z* for 95% CI = 1.96

Then applying the expression

CI = x ± z * δ/√n

Cl = 70.2±3.761

= 70.2 ± 3.761  bpm

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: