The graph of y = ax2 + bx + c is a parabola that opens up and has a vertex at (0, 5). what is the solution set of the related equation 0 = ax2 + bx + c?

The equation 0 = ax2 + bx + c has no real roots or no solution.

Step-by-step explanation:

We are told that the graph of y = ax2 + bx + c is a parabola that opens up and has a vertex at (0, 5). Since the parabola opens up, the vertex (0, 5) will be the lowest point on the graph of the function. This implies that the parabola does not intersect the x-axis; the line y = 0. Therefore, the equation;

 0 = ax2 + bx + c will have no real roots or no solution. Find the attached.

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p