Omg pls what equation describes a line that passes through (-1,8) (5,-2)

1. The first step to answering this question is to find the gradient of the line on which the given points are situated. The formula for the gradient is given by:

m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line

Thus, given that we have the two points (-1, 8) and (5, -2), we can substitute these into the equation above to find the gradient:

m = (-2 - 8) / (5 - (-1))

m = -10 / (5 + 1)

m = -10/6

m = -5/3

2. The second step is to find the equation of the line itself. This can be achieved by substituting the gradient and one point into the formula for a straight line below:

y - y1 = m(x - x1), where m is the gradient and (x1, y1) is one point on the line

We can use either of the given points so let's use (-1, 8), and the gradient of -5/3 that we found in step 1:

y - 8 = (-5/3)(x - (-1))

y = (-5/3)(x + 1) + 8 (Add 8 to both sides)

y = (-5/3)x - 5/3 + 8 (Expand (-5/3)(x + 1) )

y = (-5/3)x + 19/3

Thus, the equation that we are looking for is y = (-5/3)x + 19/3

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.