What is the square root of  ab2?

sqrt.(a) * absolutevalue(b)

Step-by-step explanation:

You do abs value when you have an even exponent with an odd exponent result from b^2 to b^1.

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Hello there!

Well, the square root is the inverse function of the square potential.

This is if you have and

A interesting part of the square root is that (-4)*(-4) = 16, and 4*4 = 16, so the solutions for are -4 and 4. For this is that you see a +- symbol in the second equation.

Now, if you have the number

Now, we put this inside a square root:

So the solutions for the square root of (a*b)^2 are a*b and - a*b.

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step-by-step explanation: