23 points awarded and will choose ! at a game show, there are 7 people (including you and your friend) in the front row. the host randomly chooses 3 people from the front row to be contestants. the order in which they are chosen does not matter. there are 7c3 = 35 total ways to choose the 3 contestants. what is the probability that you and your friend are both chosen?

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

so, converting firstly the mixed fractions to improper fractions and then "adding".

don't report but were is the digram

step-by-step explanation: