In δpqr, sin r = [tex]rac{3}{5}[/tex]. what is cos p? (a) [tex]rac{5}{3}[/tex](b) [tex]rac{3}{4}[/tex](c) [tex]rac{4}{3}[/tex](d) [tex]rac{3}{5}[/tex](image attached below)

Since we know that ΔPQR is a right triangle, we can also asume that:sin R = cos P = 3/5So the answer...

Mathematics, 23.06.2019 20:20 tdupre14

In δpqr, sin r = $\frac{3}{5}$ . what is cos p? (a) $\frac{5}{3}$ (b) $\frac{3}{4}$ (c) $\frac{4}{3}$ (d) $\frac{3}{5}$ (image attached below)

$In δpqr, sin r = [tex]\frac{3}{5}[/tex]. what is cos p? (a) [tex]\frac{5}{3}[/tex](b) [tex]\frac{3}{$

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In δpqr, sin r = [tex]\frac{3}{5}[/tex]. what is cos p? (a) [tex]\frac{5}{3}[/tex](b) [tex]\frac{3}{...