Which line is perpendicular to a line that has a slope of line jkline lmline noline pq

Option C is correct.

Step-by-step explanation:

Slope of line JK

J (1,-6) K (0,4)

slope of JK = y₂ - y₁ / x₂ - x₁

Slope of JK = 4-1/0-(-6) = 3/6 = 1/2

so slope of JK = 1/2

Slope of line LM

L (-5,-3) and M(0,3)

slope of LM = y₂ - y₁ / x₂ - x₁

slope of LM = 3-(-5)/0-(-3) = 3+5/3 = 8/3

Slope of line NO

N(-6,-5) and 0 (0,0)

slope of NO = y₂ - y₁ / x₂ - x₁

slope of NO = 0-(-6)/0-(-5) = 6/5

So, slope of line NO = 6/5

Slope of PQ

P(-5,4) Q(0,-2)

slope of PQ = y₂ - y₁ / x₂ - x₁

slope of PQ = -2-4/0-(-5) = -2/5

so slope of line PQ = -2/5

the two lines are perpendicular if slope of one line is m then slope of other line is -1/m

The slope of given line =m= -5/6

The slope of line perpendicular to the given line = -1/m = 6/5

So, line NO is perpendicular to the given line as its slope is 6/5

Option C is correct.

4444444444444 i think

positive

step-by-step explanation:

the quadrant is facing upwards