The solution to the system of equation below is (−2, −1). 2x − 3y = −1 11x − 9y = −13 when the first equation is multiplied by −3, the sum of the two equations is equivalent to 5x = −10. which system of equations will also have a solution of (−2, −1)? 5x = −10 11x − 9y = −13 2x + 9y = −1 11x − 9y = −13 −6x + 9y = −1 11x − 9y = −13 −6x + 3y = −1 5x = −10

A) 5x = −10 , 11x − 9y= −13

Step-by-step explanation:

we have

2x-3y=-1 > equation A

11x-9y=-13 > equation B

Multiply equation A by -3

-3(2x-3y)=-1*(-3)

-6x+9y=3 > equation C

Adds equation B and equation C

11x-9y=-13

-6x+9y=3

11x-6x=-13+3

5x=-10 > equation D

11x-9y=-13 > equation B

Solve the system of equations D and B

5x=-10 > x=-2

substitute the value of x in the equation B

11(-2)-9y=-13

-22-9y=-13

9y=-22+13

9y=-9

y=-1

The solution is the point (-2,-1)

therefore

The answer is the option A

understand that i don't know the answers

will someone answer his question

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,