The equation of a linear function in point-slope form is y – y1 = m(x – x1). harold correctly wrote the equation y = 3(x – 7) using a point and the slope. which point did harold use? when harold wrote his equation, the point he used was (7, 3). when harold wrote his equation, the point he used was (0, 7). when harold wrote his equation, the point he used was (7, 0). when harold wrote his equation, the point he used was (3, 7).

For this case we must find the point that Harold used to arrive at the following equation:

Starting from the fact that the equation of the point-slope form of a line is given by:

If we compare the standard equation with Harold's, we see that the slope of the line is

In addition, it is observed that and

Then, the correct option is: Harold used the point (7,0)

When Harold wrote his equation, the point was used (7,0).

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.