Will mark brainliest, given: cd is an altitude of △ abc . prove: a^2=b^2+c^2−2bc cos a? (choices are on the bottom) cd is an altitude of △ abc > given △acd and △bcd are right triangles. > a^2=(c−x)^2+h^2 > a^2=c^2−2cx+x^2+h^2 > square the binomial. b^2=x^2+h^2 > pythagorean theorem cosa=x/b > b cos a = x > multiplication property of equality a^2=c^2−2c (b cos a) +b^2 > a^2=b^2+c^2−2bc cos a > commutative properties of addition and multiplication choices: definition of cosine definition of right triangle pythagorean theorem substitution property of equality

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.