The sides of a triangle have length x, x + 4, and 20. if the length of the longest side is 20, which value of x would make the triangle acute

See below.

Step-by-step explanation:

If the triangle is  right-angled then x = 12 and x + 4 = 16, because 20^2 = 12^2 + 16^2.

In an acute triangle if c is the hypotenuse then c^2 < a^2 + b^2 so x must be greater than 12. Also as 20 is the longest side x  cannot be 16 or greater.

So pick a value greater than 12 and less than 16.

its 14  on edg                              

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b