Abicycle racer sprints at the end of a race to clinch a victory. the racer has an initial velocity of 10.0 m/s and accelerates at the rate of 0.500 m/s2. if the racer was 300 m from the finish when starting to accelerate, what is the racer’s final velocity in m/s

20m/s

Step-by-step explanation:

This can be solved using the acceleration / velocity equations.

Specifically,

v² = u² + 2as

Where

v = final velocity = what we need to find

u = initial velocity = given as 10.0m/s

a = acceleration = given as 0.5m/s²

s = distance = 300m

Hence,

v² = 10² + (2)(0.5) (300)

    = 100 + 300

    =400

v = √400 = 20 m/s

y=x+9

?

step-by-step explanation:

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.