Abox has a length of 6 inches, a width of 8 inches, and a height of 24 inches. can a cylinder rod with a length of 63.5 centimeters fit in the box?

Yes.

Step-by-step explanation:

The longest diagonal in the box is the line between one of the top corners to the opposite bottom corner.

Calculate the length of the longest diagonal in the box:

The diagonal of the base =  √(6^2 + 8^2)

= √100 = 10 inches.

The longest diagonal = √( 24^2 + 10^2)

= √676

=  26 inches

=  26 * 2.54

=  66.04 cms.

Therefore the cylinder (length 63.5 cms) rod can fit in the box.

d

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!