The 95% confidence interval for these parts is 56.98 to 57.05 under normal operations. a systematic sample is taken from the manufacturing line to determine if the production process is still within acceptable levels. the mean of the sample is 56.96. what should be done about the production line? the 95% confidence interval for these parts is 56.98 to 57.05 under normal operations. a systematic sample is taken from the manufacturing line to determine if the production process is still within acceptable levels. the mean of the sample is 56.96. what should be done about the production line? keep the line operating as it is close to the confidence interval stop the line as it is outside the confidence interval keep the line operating as it is outside the confidence interval stop the line as it is close to the confidence interval

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

first one because it can't have a fraction in it

step-by-step explanation:

192/15 = 12.8.

12.8

step-by-step explanation:

192/15 is 12.8.

however, it says to round to the nearest foot, which would equal 13.

one way is to plot 2 points and connect them which is what the answer choices seem to be doing

it seems to be using the y intercept and the slope

y=mx+b, m=slope, b=y-intercept (where the line hits the y axis)

slope=rise/run

y-intercept is where the line croses the y axis which is the y value where x=0

you seem to have given the wrong slope (you didn't put a number in front of te x, it should be 2/3 or 3/2 looking at the answer options)

y=? x-1

m=? because of your fault

b=-1

so it has a slope of ? and y intercept of -1, meaning it pases through (0,-1)

so draw point (0,-1) (so answer is one of the first 2 option)

if slope is 2/3, then go up 2 and right 3 then draw line through those 2 points

if slope is 3/2, then go up 3 and right 2 then draw line through those 2 points