45 points! asap and ill mark as brainliest! what are the amplitude, period, and midline of the function? (1 point) amplitude: 8; period: π; midline: y = 1 amplitude: 8; period: 2π; midline: y = 5 amplitude: 4; period: 2π; midline: y = 5 amplitude: 2; period: π; midline: y = 1

Amplitude = 2; period T = π; midline y = 1.

This sinusoidal wave is a even function which means that it has a positive half-cycle and a negative half-circle of equal size, from the image we can see that the midline is y = 1 which is the point where the function is centered.

The amplitude is the measure from the midline to the positive half-cycle, and the midline to the negative half-cycle which is 2.

The period corresponds to a complete cycle of the function or the repetition of the wave seen from a point. In this case, we can see that the wave, starting from π/2 it repeat in 3π/2. So, to calculate the period just substract 3π/2 by π/2

T = 3π/2 - π/2 = (3π - π)/2

T = 2π/2

T = π

8 apples are left.

step-by-step explanation:

10-2=8

10 apples

take 2

now u have 8

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho