Write the point-slope form of an equation for a line that passes through the point with the given slope (–6, –6), slope = -4/7 a. y – 6 = -4/7(x + 6) c. y + 6 =-4/7(x + 6) b. y + 6 = -4/7(x – 6) d. y + 6 = -4/7(x + 6)

see explanation

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = - and (a, b) = (- 6, - 6), hence

y - (- 6) = - (x - (- 6) ), that is

y + 6 = - (x + 6) ← c or d

y + 6 = -4/7(x + 6)

Step-by-step explanation:

The point-slope form of an equation for a line that passes through a point

( a, b )with a slope m is given as;

we substitute the given values into the given equation above and simplify. Our point is given as (–6, –6) while the slope is -4/7;

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)