Water is being pumped into a 12-foot-tall cylindrical tank at a constant rate. • the depth of the water is increasing linearly. • at 2: 30 p. m., the water depth was 2.6 feet. • it is now 5: 00 p. m., and the depth of the water is 3.6 feet. what will the depth (in feet) of the water be at 6: 00 p. m.?

4 feet

Step-by-step explanation:

It is given that:

• At 2:30 p.m., the water depth was 2.6 feet.  

• It is now 5:00 p.m., and the depth of the water is 3.6 feet.

So in 2.5 hours ( 5pm - 2:30pm) the water rose 1 feet (3.6 - 2.6).

Now we can find how much water rises in 1 hour by setting up a ratio (let x be the depth increase of water in 1 hr):

So, in 1 hour, the water level will rise 0.4 feet

So, at 6pm (1 hour from 5 pm) it will rise to 3.6 + 0.4 = 4 feet

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!