Find the value of k for which one root of the quadratic equation kx2 14x 8 = 0 is 6 times the other

k = 3.

Step-by-step explanation:

If the 2 roots are A and B we have the relations:

AB = 8/k and A+B = -14/k.

We are given that A = 6B so

6B^2 = 8/k

B^2 = 8/6k = 4/3k

B = 2 /√(3k) (1)

Now A + B = -14/k so

6B + B = 7B = -14/k

B = -2/k(2)

Eliminating B from equations (1) and (2):

2 /√(3k) = -2/k

Cross multiply:

2k = -2√(3k)

Squaring both sides:

4k^2 = 4 * 3k

4k^2 = 12k

k^2 = 3k

k = 3.

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

its adding 5.5 each time

step-by-step explanation: