There are 5 boys and 5 girls on a co-ed basketball team. a team plays 5 players on the court at one time, and the team can have at most 3 boys. how many possible teams can be created?

226 teams

Step-by-step explanation:

A team can be:

Count all combinations:

1. 5 girls from 5 girls can be chosen in 1 way.

2. 4 girls from 5 girls can be chosen in

different ways and 1 boy from 5 boys can be chosen in

different ways, so in total,

different combinations.

3. 3 girls from 5 girls can be chosen in

different ways and 2 boys from 5 boys can be chosen in

different ways, so in total,

different combinations.

4. 2 girls from 5 girls can be chosen in

different ways and 3 boys from 5 boys can be chosen in

different ways, so in total,

different combinations.

In total, there are

possible teams.

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)