5. a walkway is formed by four semicircles as shown below. the diameter of theinner semicircles is 14 feet. the width between the outer and inner semicirclesis 2 feet. find the area of the walkway. use 3.14 as an approximation for2

answer:  

\boxed {\frac{1}{5}}  

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solution-

60 *   \frac{1}{5}   = 12

90 * \frac{1}{5} = 18

75 * \frac{1}{5} = 15

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hence, the answer would be \boxed {\frac{1}{5}}