Mathematics, 26.06.2019 19:00 coolcat3190

Simplify the expression. sine of x to the second power minus one divided by cosine of negative x

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Answer from: pillgiing

the answer is the letter a) -sin x

Step-by-step explanation:

Simplify the expression.

sine of x to the second power minus one divided by cosine of negative x

(1−sin2(x))/(sin(x)−csc(x))

sin2x+cos2x=11−sin2x=cos2x

cos2(x)/(sin(x)−csc(x))csc(x)=1/sin(x)cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))sin2(x)− 1=-cos2(x)cos2(x)/(( -cos2(x))/sin(x))

=-sin(x)

Answer from: jerria73

$-cos \ x$

Step-by-step explanation:

First of all, we must have to understand what is the described expression in the paragraph

"sine of x to the second power minus one divided by cosine of negative x"

In this sentence, we need to identify what are the elements and operations involved in the expression.

In the sentence appears ""to the second power", "minus" and "divided by" (highlighted)

"sine of x to the second power minus one divided by cosine of negative x"

Therefore, the expression must has three operations:

"to the second power": refers to exponentiation"minus": refers to a substraction"divided by": refers to a division

Now, we can identify what are the elements: "sine of x", "one" and "cosine of negative x"

"sine of x": refers to $sin\ x$ "one": refers to the number one (1)"cosine of negative x": refers to cos (-x)

Therefore, the expression is:

$\frac{(sin\ x)^{2}-1}{cos(-x)}$

In order to find the simplified expression, we must have to apply these trigonometric identities:

$(sin\ x)^{2} = sin^{2}x$ $sen\x^{2}x \ +\ cos\x^{2}x=1$ $cos(-x)=cos\ x$

Applying the first and third identities, we have:

$\frac{(sin\ x)^{2}-1}{cos(-x)}=\frac{sin\x^{2}x-1}{cos\ x}$

From the second trigonometric identity, we have:

$cos\x^{2}x=\ 1-sin\x^{2}x$

Now, multiplying by -1 in both sides:

$(-1)(cos\x^{2}x)=(-1)(1-\ sin\x^{2}x)$

In the left side, multiplying by -1 the sign of the expression changes:

$(-1)(cos\x^{2}x)=-cos\x^{2}x$

In the right side, multiplying by -1 changes the order of the substraction:

$(-1)(1-\ sin\x^{2}x)=\ sin\x^{2}x-1$

Putting all together:

$-cos\x^{2}x=\ sin\x^{2}x-1$

Now, replacing values we have:

$\frac{sin\x^{2}x-1}{cos\ x}=\frac{-cos\x^{2}x}{cos\ x}=-\frac{cos\x^{2}x}{cos\ x}$

Finally, the property of the first trigonometric identity (property of exponentiation) can be apply in this case:

$-\frac{cos\x^{2}x}{cos\ x}=-\frac{(cos\ x)^{2}}{cos\ x}=-cos\ x$

Answer from: Quest

all about the same size in the city the game was

step-by-step explanation:

Answer from: Quest

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it

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Simplify the expression. sine of x to the second power minus one divided by cosine of negative x...