Jeremys father is 11 less than jermeys age squared. if jeremy’s father is 53, how many years older is jeremy’s father than jeremy?

45 years

Step-by-step explanation:

First, lets break the problem down, step-by-step.

Jeremy's age can be represented using the varibale, j.

His father's age is 53, or 11 less than j squared.

Jeremy's father's age can be represented using the following equation:

j^2 - 11 = 53

Now, solve for j.

j^2 - 11 = 53

j^2 = 64

j = 8

That means Jeremy is 8 years old. Now, find the difference between his age and his father's age.

53 - 8 = 45.

So, Jeremy's father is 45 years older than his son.

I hope this helps! :)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

351°f

step-by-step explanation: