Abag contains 12 balls numbered from 1 to 12. two balls are selected from the bag one at a time, without replacement. (order matters) let event e = the two numbers have a sum of 5. how many outcomes are in the complement of e?

i think the answer is b

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.

there is no picture in order for this question to be answered