Aquadratic equation of the form 0=ax^2+bx+c has a discriminate value of -16. how many real number solutions does this equation have?

ANSWER

0

EXPLANATION

The discriminant of a quadratic equation in the form

is given by

The discriminant of a quadratic equation tells us the nature of the roots of that quadratic equation.

If the discriminant is negative, the equation has no real roots.

If the discriminant us positive, the equation has two real roots.

If the discriminant is zero, the equation has a repeated root.

Since the discriminant is -6, the equation has no real roots.

In other words, the number of real roots is 0.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.