Which correspondence is equivalent to δ pqr↔δstu? a) δ rqp ↔ δuts? b) δ prq ↔ δtus? c) δ rpq ↔ δsut? d) δ qrp ↔ δust?

Option A) is correct

Step-by-step explanation:

Given :

We need to find which correspondence is equivalent to .

Solution :

One to one correspondence means measure of each side and each angle of one triangle is equal to the side and angle of the other triangle .

Here, we observe that option A) is equivalent to as explained below :

As per ,

Also, as per , we have

Therefore,

is equivalent to

So, option A) is correct .

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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step-by-step explanation: