Mathematics, 10.09.2020 14:01 Tcutety

8 (4p + 1) = 32p +8
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$8(4p+1)=32p+8 \\\\ 32p+8=32+8 \\\\ 32p-32p=8-8 \\\\ \boxed{0=0}\\\\ p \ can \ take any \ value \ because \ every \ number \ would \ make \ the \ sentence \ true.$

Answer from: bellam302

What is your question ? Are you asking for the solution of the equation ?

The "solution" is the number that 'p' must be, in order to make the equation
a true statement.

When you eliminate the parentheses on the left side of the equation,
the left side becomes 32p + 8 .

Then the equation says 32p + 8 = 32p + 8 .

That's a true statement no matter what 'p' is .

So any number and every number is a solution of the equation.

Answer from: Quest

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

Answer from: Quest

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

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