What values for θ (0 ≤ θ ≤ 2π) satisfy the equation? 2 sin θ cos θ + root3 cos θ = 0?

Step-by-step

Given equation:

2sin(theta)cos(theta) + sqrt(3)*cos(theta) = 0  ...........................(1)

Solve for theta for 0<=theta<=2pi.

Factor out cos(theta), we get

cos(theta) * ( 2sin(theta) + sqrt(3) ) = 0

By the zero product theorem, we can conclude

cos(theta) = 0   ...................................(2)

OR  

2sin(theta) + sqrt(3) = 0  ................. (3)

Solving (2)

cos(theta) = 0 has solutions pi/2 or 3pi/2  from the cosing curve.

Solving (3)

2sin(theta) + sqrt(3) = 0  =>

sin(theta) = -sqrt(3)/2

which has solutions  4pi/3 or 5pi/3.

So the solutions to equation (1) are

S={pi/2,  4pi/3, 3pi/2, 5pi/3}

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!