5) find the equation of the line graphed below in slope-intercept form. (3 points) 6) find the equation of the line graphed below in point-slope form. (4 points)

5. Slope intercept form is written as y = mx +b, where m is the slope and b is the y-intercept.

Using two of the points on the graph find the slope:

(0,-3) and (6,1)

Slope = change in Y over the change in X:

Slope =  (1-(-3) / (6-0) = 4/6 = 2/3

The y-intercept is the Y value when x = 0, which is -3.

The formula is y = 2/3x - 3

6. Point slope form is written as y - y1 = m(x- x1) where m is the slope, y1 and x1 are a known point on the line.

Slope = (1-0) / (1-3) = 1/-3 = -1/3

You can use either point shown for x1 and y1, so I am using the point (1,1)

The equation becomes y -1 = -1/3(x-1)

could you reply to this with the question so i can ?